1 Topic by Paul

  • Paul
  • Senior Member
  • Offline
  • From: Wales, UK.
  • Registered: 2003-08-13
  • Posts: 3,089

Topic: Help - Regular Expressions/String Replacement

The aim is to locate two <br />'s in a row which are followed by anthing which is not a <br /> and then replace the two line breaks with something else. The two line breaks could appear at the end of a long string of line breaks and I only want to replace the last two. I also don't want to touch whatever comes after the last two line breaks. Is there a simple one line server/speed friendly bit of code which accomplishes this. If you want a clearer example

blah blah
<br />
<br />
<br />
<br />
blah blah

becomes

blah blah
<br />
<br />
</p>
<p>
blah blah

  • From: 127.0.0.1
  • Registered: 2001-11-02
  • Posts: 9,167

Re: Help - Regular Expressions/String Replacement

Something like this should do the job:

$text = preg_replace('#<br />\s*?<br />(?!\s*<br />)#i', "</p>\n<p>", $text);
"Programming is like sex: one mistake and you have to support it for the rest of your life."

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3 Reply by Paul

  • Paul
  • Senior Member
  • Offline
  • From: Wales, UK.
  • Registered: 2003-08-13
  • Posts: 3,089

Re: Help - Regular Expressions/String Replacement

Great, that works. With the addition of a few tabs the output is a joy to behold.