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No, there are no templates in the sense you're thinking of. If you're talking about just replacing the link in the navlinks, that's include/functions.php, in the generate_navlinks function. If you're talking about replacing the link elsewhere (eg: viewtopic.php), that's within those files most likely.

Sounds like a wonderful extension, but certainly not a feature for the core

I'm not exactly sure what you mean by "unlike the main punbb principles"
However, the online/offline texts can be determined via CSS I believe: if you want to have a style that replaces them, you're certainly free to

Delete profile.php, replace all references to it with references to your page?

You can already see guests online on the front page (and I don't see where you can come up with a "total" for that).
Same with number of users online (although there you can get a total).
Alexa rank is completely useless
So yes, that would be better off as an extension

Example?

I think that's something that can be left up to each forum administrator.

There is no PHP variable, the assumption of 1=Guest is used in various places in the code.
foxmask: Just changing the ID in the database does nothing but break the forum.
You would probably find it easier to assign your user a new ID

Yes. You could also just have the equivalent of disp_position

I removed that image from your signature, it was way too tall

Quick jump        Yes    No  Enable the quick jump (jump to forum) drop list.
It's in admin options

LIMIT '.$min.', '.$max

I don't think you did, because it looks like I'm getting the same value for form_user as I did. Then again, it's hard to know on your forum what the value of username is versus email versus firstname.

Paste a copy of your post.php?

http://dev.mysql.com/doc/refman/5.0/en/join.html

#

If there is no matching row for the right table in the ON or USING part in a LEFT JOIN, a row with all columns set to NULL is used for the right table. You can use this fact to find rows in a table that have no counterpart in another table:

SELECT left_tbl.*
  FROM left_tbl LEFT JOIN right_tbl ON left_tbl.id = right_tbl.id
  WHERE right_tbl.id IS NULL;

This example finds all rows in left_tbl with an id value that is not present in right_tbl (that is, all rows in left_tbl with no corresponding row in right_tbl). This assumes that right_tbl.id is declared NOT NULL. See Section 6.2.8, ?LEFT JOIN and RIGHT JOIN Optimization?.

That's the major difference